Link Search Menu Expand Document

Series

We will cover following topics

Series And Its Convergence

Any ordered infinite sequence of terms is called a series, and is denoted by i=1ai.

A series n1an converges if the sequence of the partial sums of the series converges.

The sequence of partial sums is defined as (S1,S2,S3,...,Sn), where Sn=k=1nakl

For example, n=11n(n+1) converges because Sn=11n+11. Similarly, for 0<x<1, the geometric series n=0xn converges to 11x because Sn=1xn+11x.

A necessary condition for n=1an to converge is that an0. For example, for |x|1, n=1xn diverges because an0. Similarly, n=1sinn diverges because an0.

The above condition is necessary but not sufficient. For example, n=1log(n+1n) diverges, however, log(n+1n)0.

Necessary and Sufficient Condition for Convergence

Theorem 1

Let an0  n. Then, n=1an converges if and only if the partial sum Sn is bounded above.

For example, the harmonic series n=11n diverges because

S2k1+12+214+418++2k112k=1+k2

which diverges as k.


Theorem 2

If n=1|an| converges, then n=1an converges.


Comparison Test

If 0anbn for nk. Then,

(i) If n=1bn converges n=1an converges.

For example, n=11(n)2 converges because 1(n)(n)1n(n1).

Here, 1n(n1) is a difference series which converges to 1 as n. Therefore, n=11n2 converges.

Based on this result, we can also say that n=11n! converges because 1n!<1n2 for n>5.

(ii) If n=1an diverges, n=1bn diverges.

For example, n=11n diverges because 1n1n and the harmonic series n=11n diverges.


Limit Comparison Test

Let an,bn0 and let anbnL. Then,

If L if positive and finite, then either both series converge or both series diverge.

Absolute And Conditional Convergence Of Series

Absolute Convergence

A series t=0an is said to converge absolutely if n=0|an|=L for some real number L.


Conditional Convergence

A series n1an converges conditionally if n1an converges but the series n1|an| diverges.

Rearrangement Of Series

Riemann Series Theorem: It says that if an infinite series of real numbers is conditionally convergent, then its terms can be arranged in a permutation so that the new series coverges to an arbitrary real number, or diverges.


PYQs

Series And Its Convergence

1) Find the range of p(>0) for which the series:

1(1+a)p1(2+a)p+1(3+a)p....,a>0, is

(i) absolutely convergent and (ii) conditionally convergent.

[2018, 10M]

Use comparison and Leibnitz tests.

2) Show that the series n=1(1)n+1n+1 is conditionally convergent. (If you use any theorem, (s) to show it, then you must give a proof of that theorem(s)).

[2016, 15M]

Use Leibnitz test

3) Test the convergence and absolute covergence of the series n=1(1)n+1(nn2+1).

[2015, 10M]

Use Leibnitz test

4) Show that the series n=1(ππ+1)nn6 is convergent.

[2012, 12M]

Use ratio test.

5) Show that the series (13)2+(1.43.6)2+.+(1.4.7..(3n2)3.6.9..3n)2 till infinity, converges.

[2009, 15M]

Use Rabee's test.

6) Find all the positive values of a for which the series n=1(an)nn! converges.

[2002, 12M]

Use ratio test.

Rearrangement of Series

1) Let n=1xn be a conditionally convergent series of real numbers. Show that there is a rearrangement n=1xπ(n) of the series n=1xn that converges to 100.

[2017, 20M]


2) Show that the series 1n(n+1) is equivalent to 122(1+1n21).

[2008, 15M]


3) Rearrange the series n=1(1)n+11n to converge to 1.

[2007, 20M]


< Previous Next >