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Integrals

We will cover following topics

Riemann Integral

Let [a,b] be a given interval. A partition P of [a,b] is a finite set of points x0, x1, x2,…xn such that a=x0x1xn1xn=b and is denoted by P={x0,x1,x2,,xn}.

  • The upper Riemann sum is given by:

    U(P,f)=1nMiΔxi

    where Mi=sup{f(x):xi1xxi} and Δxi=xixi1

  • The lower Riemann sum is given by:

    L(P,f)=1nmiΔxi

    where mi=inf{f(x):xi1xxi} and Δxi=xixi1

    Since f is bounded, real numbers m and M such that mf(x)M x[a,b]. Thus, for every partition P,

    m(ba)L(P,f)U(P,f)M(ba)

We define:

  • The upper Riemann integral of f over [a,b] as abfdx=infU(P,f).

  • The lower Riemann integral of f over [a,b] as abfdx=supL(P,f).

Riemann Integral: f is said to be Riemann integrable or integrable if the upper and lower integrals of f are equal and the common value is called the Riemann integral of f, denoted by abfdx.

Improper Integrals

Improper integrals are integrals which are defined for either bounded functions defined on unbounded intervals, or unbounded functions defined over bounded (or unbounded) intervals.

Improper Integral of First Kind

Let f be Riemann integrable on [a,x] x>a.

If limxaxf(t)dt=L, for some LR, then we say that the improper integral of first kind, af(t)dt, converges to L, and is denoted by af(t)dt=L.

Otherwise, the improper integral af(t)dt is said to diverge.

Example: The improper integral 11t2dt converges because 1x1t2dt=11x1 as x. On the other hand, the improper integral 11tdt diverges because limx1x1tdt=limxlogx as x.

We can show that 11tpdt converges to 1p1 for p>1 and diverges for p1.

Comparison Test and Limit Comparison Test

Suppose f is integrable on [a,x] x>a. Then, we state following two theorems:

Comparison Test: Let 0f(t)g(t) t>a. Then,

If ag(t)dt converges, af(t)dt converges.


Limit Comparison Test (LCT): Let f(t), g(t)0  x>a.

If limtf(t)g(t)=c, where c0, then both the integrals af(t)dt and ag(t)dt converge  either converge, or diverge together.

If c=0, the convergence of ag(t)dt implies the convergence of af(t)dt.

Example: The integral 1sin1tdt diverges by LCT because sin1t1t1 as t. On the other hand, for pR, 1ettpdt converges by LCT because ettpt20 as x.

Theorem

If an improper integral a|f(t)|dt converges, then af(t)dt converges.

Dirichlet Test

Let f,g:[a,)R be such that: (i) f is decreasing and f(t)0 as t, (ii) g is continuous and M such that azg(t)dtM x>a. Then, af(t)g(t)dt converges.

Improper Integral of Second Kind:

Let xbf(t)dt exists x such that a<xb.

If limxa+xbf(t)dt=M for some mR, then the improper integral of second kind, abf(t)dt is said to converge at M and is denoted by abf(t)dt=M.

Fundamental Theorems Of Integral Calculus

First Fundamental Theorem of Calculus

Let f be integrable on [a,b]. For axb, let F(x)=axf(t)dt. Then, F is continuous on [a,b].

Also, if f is continuous at x0, then F is differentiable at x0 and F(x0)=(x0).


Second Fundamental Theorem of Calculus

Let f be integrable on [a,b]. If there is a differentiable function F on [a,b] such that F=f, then abf(x)dx=F(b)F(a).


Riemann Sum

Let f:[a,b]R and let P={x0,x1,,xn} be a partition of [a,b].

Let ck[xk1,xk], k=1, 2,.., n. Then, corresponding to the partition P and the intermediate points ck, a Riemann sum for f is defined as S(P,f)=k=1nf(ck)Δxk.

Also, the norm of P is defined as P=max1inΔxi.


Theorem

Let f:[a,b]R be integrable. Then, limP0S(P,f)=abf(x)dx.


PYQs

Riemann Integral

1) Evaluate

0tan1(ax)x(1+x2)dxa>0,a1

[2019, 10M]


2) Prove the inequality: π29<π6π2xsinxdx<2π29

[2018, 10M]


3) Is the function
f(x)={1n,1n+1<x1n0,x=0
Riemann integrable? If yes, obtain the value of 01f(x)dx

[2015, 15M]


4) Integrate 10f(x)dx, where f(x)={2xsin1xcos1x,x[0,1]0,x=0

[2014, 15M]


5) Let f(x)={x22+4 if x0x22+2 if x<0

Is f Riemann integrable in the interval [1,2]? Does there exist a function g such that g(x)=f(x)? Justify your answer.

[2013, 10M]


6) Let [x] denotes the integer part of the real number x, i.e., if nx<n+1 where n is an integer, then [x]=n. Is the function f(x)=[x]2+3 Riemann integrable in the interval [1,2] If not, explain why. If it is integrable, compute 12([x]2+3)dx.

[2013, 10M]


7) Give an example of a function f(x), that is not Riemann integrable but |f(x)| is Riemann integrable. Justify your answer.

[2012, 20M]


8) Show that the function f(x) defined as
f(x)=12n, 12n+1x12n, n=0,1,2, and f(0)=0 is integrable in [0,1], although it has an infinite number of points of discontinuity. Show that 01f(x)dx=23.

[2004, 12M]


9) A function f is defined in the interval (a,b) as follows:
f(x)={1q2 when x=pq1q3 when x=pq
where p, q are relatively prime integers.
f(x)=0 for all other values of x.
Is f Riemann integrable? Justify your answer.

[2001, 20M]


Multiple Integrals

1) Find the volume of the solid in the first octant bounded by the paraboloid z=364x29y2.

[2007, 20M]


2) Find the volume of the ellipsoid

x2a2+y2b2+z2c2=1

[2006, 20M]


3) Evaluate

ln(x+y+z)dxdydz

[2005, 12M]


4) Find the volume bounded by the paraboloid x2+y2=az, the cylinder x2+y2=2ay and the plane z=0.

[2004, 20M]


5) The axes of two equal cylinders intersect at right angles. If a be their radius, then find the volume common to cylinders by the method of multiple integrals.

[2003, 20]


6) A solid hemisphere H of radius a has density ρ depending on the distance R from the centre and is given by: ρ=k(2aR), where k is a constant.

Find the mass of the hemisphere, by the method of multiple integrals.

[2002, 15M]


7) Evaluate (ax2+by2+cz2)dxdydz taken throughout the region x2+y2+z2R2.

[2001, 15M]


Improper Integrals

1) Discuss the convergence of 12xlnxdx.

[2019, 15M]


2) Test the convergence of the improper integral 1dxx2(1+ex).

[2014, 10M]


3) Examine the convergence of 01dxx1/2(1x)1/2.

[2006, 12M]


4) Show that 0ettn1dt is an improper integral which converges for n>0.

[2005, 30M]


5) Show that 0dx1+x2sin2x is divergent.

[2003, 20M]


6) Prove that the integral 0xm1exdx is convergent if and only if m>0.

[2002, 12M]


7) Show that 0π/2xnsinmxdx exists if and only if m<n+1.

[2001, 12M]


Fundamental Theorems Of Integral Calculus

1) Let f(x) be differentiable on [0,1] such that f(1)=0 and 01f2(x)dx=1. Prove that 01xf(x)f(x)dx=12.

[2012, 15M]


2) Let f be a continuous function on [0,1]. Using first Mean Value theorem on Integration, prove that limn01nf(x)1+n2x2dx=π2f(0).

[2008, 15M]


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